6(2v-8)=8v+4(1+2v)

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Solution for 6(2v-8)=8v+4(1+2v) equation: 



6(2v-8)=8v+4(1+2v)

We move all terms to the left:

6(2v-8)-(8v+4(1+2v))=0

We add all the numbers together, and all the variables

6(2v-8)-(8v+4(2v+1))=0

We multiply parentheses

12v-(8v+4(2v+1))-48=0



We calculate terms in parentheses: -(8v+4(2v+1)), so:

8v+4(2v+1)

We multiply parentheses

8v+8v+4

We add all the numbers together, and all the variables

16v+4

Back to the equation:

-(16v+4)



We get rid of parentheses

12v-16v-4-48=0

We add all the numbers together, and all the variables

-4v-52=0

We move all terms containing v to the left, all other terms to the right

-4v=52

v=52/-4

v=-13

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