6(2t-5)+2(3t-7)=-26

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Solution for 6(2t-5)+2(3t-7)=-26 equation: 



6(2t-5)+2(3t-7)=-26

We move all terms to the left:

6(2t-5)+2(3t-7)-(-26)=0

We add all the numbers together, and all the variables

6(2t-5)+2(3t-7)+26=0

We multiply parentheses

12t+6t-30-14+26=0

We add all the numbers together, and all the variables

18t-18=0

We move all terms containing t to the left, all other terms to the right

18t=18

t=18/18

t=1

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