6(2t-4)=7(t-2)

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Solution for 6(2t-4)=7(t-2) equation: 



6(2t-4)=7(t-2)

We move all terms to the left:

6(2t-4)-(7(t-2))=0

We multiply parentheses

12t-(7(t-2))-24=0



We calculate terms in parentheses: -(7(t-2)), so:

7(t-2)

We multiply parentheses

7t-14

Back to the equation:

-(7t-14)



We get rid of parentheses

12t-7t+14-24=0

We add all the numbers together, and all the variables

5t-10=0

We move all terms containing t to the left, all other terms to the right

5t=10

t=10/5

t=2

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