6(2t+1)+15=4t+3(t+2)

Solution for 6(2t+1)+15=4t+3(t+2) equation:

Simplifying
6(2t + 1) + 15 = 4t + 3(t + 2)

Reorder the terms:
6(1 + 2t) + 15 = 4t + 3(t + 2)
(1 * 6 + 2t * 6) + 15 = 4t + 3(t + 2)
(6 + 12t) + 15 = 4t + 3(t + 2)

Reorder the terms:
6 + 15 + 12t = 4t + 3(t + 2)

Combine like terms: 6 + 15 = 21
21 + 12t = 4t + 3(t + 2)

Reorder the terms:
21 + 12t = 4t + 3(2 + t)
21 + 12t = 4t + (2 * 3 + t * 3)
21 + 12t = 4t + (6 + 3t)

Reorder the terms:
21 + 12t = 6 + 4t + 3t

Combine like terms: 4t + 3t = 7t
21 + 12t = 6 + 7t

Solving
21 + 12t = 6 + 7t

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '-7t' to each side of the equation.
21 + 12t + -7t = 6 + 7t + -7t

Combine like terms: 12t + -7t = 5t
21 + 5t = 6 + 7t + -7t

Combine like terms: 7t + -7t = 0
21 + 5t = 6 + 0
21 + 5t = 6

Add '-21' to each side of the equation.
21 + -21 + 5t = 6 + -21

Combine like terms: 21 + -21 = 0
0 + 5t = 6 + -21
5t = 6 + -21

Combine like terms: 6 + -21 = -15
5t = -15

Divide each side by '5'.
t = -3

Simplifying
t = -3