6(2r+3)=8(2r+3)+2

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Solution for 6(2r+3)=8(2r+3)+2 equation: 



6(2r+3)=8(2r+3)+2

We move all terms to the left:

6(2r+3)-(8(2r+3)+2)=0

We multiply parentheses

12r-(8(2r+3)+2)+18=0



We calculate terms in parentheses: -(8(2r+3)+2), so:

8(2r+3)+2

We multiply parentheses

16r+24+2

We add all the numbers together, and all the variables

16r+26

Back to the equation:

-(16r+26)



We get rid of parentheses

12r-16r-26+18=0

We add all the numbers together, and all the variables

-4r-8=0

We move all terms containing r to the left, all other terms to the right

-4r=8

r=8/-4

r=-2

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