6(2q-10)=-q+5

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Solution for 6(2q-10)=-q+5 equation: 



6(2q-10)=-q+5

We move all terms to the left:

6(2q-10)-(-q+5)=0

We add all the numbers together, and all the variables

6(2q-10)-(-1q+5)=0

We multiply parentheses

12q-(-1q+5)-60=0

We get rid of parentheses

12q+1q-5-60=0

We add all the numbers together, and all the variables

13q-65=0

We move all terms containing q to the left, all other terms to the right

13q=65

q=65/13

q=5

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