6(2n-1)-5=7(3n-2)+24

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Solution for 6(2n-1)-5=7(3n-2)+24 equation: 



6(2n-1)-5=7(3n-2)+24

We move all terms to the left:

6(2n-1)-5-(7(3n-2)+24)=0

We multiply parentheses

12n-(7(3n-2)+24)-6-5=0



We calculate terms in parentheses: -(7(3n-2)+24), so:

7(3n-2)+24

We multiply parentheses

21n-14+24

We add all the numbers together, and all the variables

21n+10

Back to the equation:

-(21n+10)



We add all the numbers together, and all the variables

12n-(21n+10)-11=0

We get rid of parentheses

12n-21n-10-11=0

We add all the numbers together, and all the variables

-9n-21=0

We move all terms containing n to the left, all other terms to the right

-9n=21

n=21/-9

n=-2+1/3

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