6(2n-1)+3=2n-8+5(2n+1)

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Solution for 6(2n-1)+3=2n-8+5(2n+1) equation: 



6(2n-1)+3=2n-8+5(2n+1)

We move all terms to the left:

6(2n-1)+3-(2n-8+5(2n+1))=0

We multiply parentheses

12n-(2n-8+5(2n+1))-6+3=0



We calculate terms in parentheses: -(2n-8+5(2n+1)), so:

2n-8+5(2n+1)

determiningTheFunctionDomain
2n+5(2n+1)-8

We multiply parentheses

2n+10n+5-8

We add all the numbers together, and all the variables

12n-3

Back to the equation:

-(12n-3)



We add all the numbers together, and all the variables

12n-(12n-3)-3=0

We get rid of parentheses

12n-12n+3-3=0

We add all the numbers together, and all the variables

=0

n=0/1

n=0

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