6(2n+3)=9(7n+4)+1

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Solution for 6(2n+3)=9(7n+4)+1 equation: 



6(2n+3)=9(7n+4)+1

We move all terms to the left:

6(2n+3)-(9(7n+4)+1)=0

We multiply parentheses

12n-(9(7n+4)+1)+18=0



We calculate terms in parentheses: -(9(7n+4)+1), so:

9(7n+4)+1

We multiply parentheses

63n+36+1

We add all the numbers together, and all the variables

63n+37

Back to the equation:

-(63n+37)



We get rid of parentheses

12n-63n-37+18=0

We add all the numbers together, and all the variables

-51n-19=0

We move all terms containing n to the left, all other terms to the right

-51n=19

n=19/-51

n=-19/51

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