6(2n+3)=7(4n+3)+2

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Solution for 6(2n+3)=7(4n+3)+2 equation: 



6(2n+3)=7(4n+3)+2

We move all terms to the left:

6(2n+3)-(7(4n+3)+2)=0

We multiply parentheses

12n-(7(4n+3)+2)+18=0



We calculate terms in parentheses: -(7(4n+3)+2), so:

7(4n+3)+2

We multiply parentheses

28n+21+2

We add all the numbers together, and all the variables

28n+23

Back to the equation:

-(28n+23)



We get rid of parentheses

12n-28n-23+18=0

We add all the numbers together, and all the variables

-16n-5=0

We move all terms containing n to the left, all other terms to the right

-16n=5

n=5/-16

n=-5/16

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