6(2n+1)=6(5n+3)+7

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Solution for 6(2n+1)=6(5n+3)+7 equation: 



6(2n+1)=6(5n+3)+7

We move all terms to the left:

6(2n+1)-(6(5n+3)+7)=0

We multiply parentheses

12n-(6(5n+3)+7)+6=0



We calculate terms in parentheses: -(6(5n+3)+7), so:

6(5n+3)+7

We multiply parentheses

30n+18+7

We add all the numbers together, and all the variables

30n+25

Back to the equation:

-(30n+25)



We get rid of parentheses

12n-30n-25+6=0

We add all the numbers together, and all the variables

-18n-19=0

We move all terms containing n to the left, all other terms to the right

-18n=19

n=19/-18

n=-1+1/18

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