6(2m-2)=3m=2m-18+m

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Solution for 6(2m-2)=3m=2m-18+m equation: 



6(2m-2)=3m=2m-18+m

We move all terms to the left:

6(2m-2)-(3m)=0

We add all the numbers together, and all the variables

-3m+6(2m-2)=0

We multiply parentheses

-3m+12m-12=0

We add all the numbers together, and all the variables

9m-12=0

We move all terms containing m to the left, all other terms to the right

9m=12

m=12/9

m=1+1/3

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