6(2l+1)=41

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Solution for 6(2l+1)=41 equation: 



6(2l+1)=41

We move all terms to the left:

6(2l+1)-(41)=0

We multiply parentheses

12l+6-41=0

We add all the numbers together, and all the variables

12l-35=0

We move all terms containing l to the left, all other terms to the right

12l=35

l=35/12

l=2+11/12

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