6(2g+1.5)=3(g+2)

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Solution for 6(2g+1.5)=3(g+2) equation: 



6(2g+1.5)=3(g+2)

We move all terms to the left:

6(2g+1.5)-(3(g+2))=0

We multiply parentheses

12g-(3(g+2))+9=0



We calculate terms in parentheses: -(3(g+2)), so:

3(g+2)

We multiply parentheses

3g+6

Back to the equation:

-(3g+6)



We get rid of parentheses

12g-3g-6+9=0

We add all the numbers together, and all the variables

9g+3=0

We move all terms containing g to the left, all other terms to the right

9g=-3

g=-3/9

g=-1/3

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