6(2f+5)=4(7-f)

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Solution for 6(2f+5)=4(7-f) equation: 



6(2f+5)=4(7-f)

We move all terms to the left:

6(2f+5)-(4(7-f))=0

We add all the numbers together, and all the variables

6(2f+5)-(4(-1f+7))=0

We multiply parentheses

12f-(4(-1f+7))+30=0



We calculate terms in parentheses: -(4(-1f+7)), so:

4(-1f+7)

We multiply parentheses

-4f+28

Back to the equation:

-(-4f+28)



We get rid of parentheses

12f+4f-28+30=0

We add all the numbers together, and all the variables

16f+2=0

We move all terms containing f to the left, all other terms to the right

16f=-2

f=-2/16

f=-1/8

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