6(2c+5)=4(c-20)-2

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Solution for 6(2c+5)=4(c-20)-2 equation: 


Simplifying
6(2c + 5) = 4(c + -20) + -2

Reorder the terms:
6(5 + 2c) = 4(c + -20) + -2
(5 * 6 + 2c * 6) = 4(c + -20) + -2
(30 + 12c) = 4(c + -20) + -2

Reorder the terms:
30 + 12c = 4(-20 + c) + -2
30 + 12c = (-20 * 4 + c * 4) + -2
30 + 12c = (-80 + 4c) + -2

Reorder the terms:
30 + 12c = -80 + -2 + 4c

Combine like terms: -80 + -2 = -82
30 + 12c = -82 + 4c

Solving
30 + 12c = -82 + 4c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-4c' to each side of the equation.
30 + 12c + -4c = -82 + 4c + -4c

Combine like terms: 12c + -4c = 8c
30 + 8c = -82 + 4c + -4c

Combine like terms: 4c + -4c = 0
30 + 8c = -82 + 0
30 + 8c = -82

Add '-30' to each side of the equation.
30 + -30 + 8c = -82 + -30

Combine like terms: 30 + -30 = 0
0 + 8c = -82 + -30
8c = -82 + -30

Combine like terms: -82 + -30 = -112
8c = -112

Divide each side by '8'.
c = -14

Simplifying
c = -14

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