6(27+4)=4(3y+6)

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Solution for 6(27+4)=4(3y+6) equation: 



6(27+4)=4(3y+6)

We move all terms to the left:

6(27+4)-(4(3y+6))=0

We add all the numbers together, and all the variables

-(4(3y+6))+631=0



We calculate terms in parentheses: -(4(3y+6)), so:

4(3y+6)

We multiply parentheses

12y+24

Back to the equation:

-(12y+24)



We get rid of parentheses

-12y-24+631=0

We add all the numbers together, and all the variables

-12y+607=0

We move all terms containing y to the left, all other terms to the right

-12y=-607

y=-607/-12

y=50+7/12

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