6(2/3-x)-3=2(3x-4)

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Solution for 6(2/3-x)-3=2(3x-4) equation: 



6(2/3-x)-3=2(3x-4)

We move all terms to the left:

6(2/3-x)-3-(2(3x-4))=0



Domain of the equation: 3-x)!=0

We move all terms containing x to the left, all other terms to the right

-x)!=-3

x!=-3/1

x!=-3

x∈R



We add all the numbers together, and all the variables

6(-1x+2/3)-(2(3x-4))-3=0

We multiply parentheses

-6x-(2(3x-4))-3+2/3*6=0

We multiply all the terms by the denominator


-6x*3*6-((2(3x-4)))*3*6+2-3*3*6=0

We add all the numbers together, and all the variables

-6x*3*6-((2(3x-4)))*3*6-52=0

Wy multiply elements

-108x*6-((2(3x-4)))*3*6-52=0

Wy multiply elements

-648x-((2(3x-4)))*3*6-52=0

We move all terms containing x to the left, all other terms to the right

-648x-((2(3x-4)))*3*6=52

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