6(2-z)/5=-z

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Solution for 6(2-z)/5=-z equation: 


z in (-oo:+oo)

(6*(2-z))/5 = -z // + z

(6*(2-z))/5+z = 0

(6*(2-z))/5+(5*z)/5 = 0

6*(2-z)+5*z = 0

12-z = 0

(12-z)/5 = 0

(12-z)/5 = 0 // * 5

12-z = 0

12-z = 0 // - 12

-z = -12 // * -1

z = 12

z = 12

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