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6(2-x)-4=-5x(x+3)
We move all terms to the left:
6(2-x)-4-(-5x(x+3))=0
We add all the numbers together, and all the variables
6(-1x+2)-(-5x(x+3))-4=0
We multiply parentheses
-6x-(-5x(x+3))+12-4=0
We calculate terms in parentheses: -(-5x(x+3)), so:We add all the numbers together, and all the variables
-5x(x+3)
We multiply parentheses
-5x^2-15x
Back to the equation:
-(-5x^2-15x)
-(-5x^2-15x)-6x+8=0
We get rid of parentheses
5x^2+15x-6x+8=0
We add all the numbers together, and all the variables
5x^2+9x+8=0
a = 5; b = 9; c = +8;
Δ = b2-4ac
Δ = 92-4·5·8
Δ = -79
Delta is less than zero, so there is no solution for the equation
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