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6(2-x)+3=-2(3x+2)
We move all terms to the left:
6(2-x)+3-(-2(3x+2))=0
We add all the numbers together, and all the variables
6(-1x+2)-(-2(3x+2))+3=0
We multiply parentheses
-6x-(-2(3x+2))+12+3=0
We calculate terms in parentheses: -(-2(3x+2)), so:We add all the numbers together, and all the variables
-2(3x+2)
We multiply parentheses
-6x-4
Back to the equation:
-(-6x-4)
-6x-(-6x-4)+15=0
We get rid of parentheses
-6x+6x+4+15=0
We add all the numbers together, and all the variables
19!=0
There is no solution for this equation
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