6(2-2v)=4(1-2v)

Solution for 6(2-2v)=4(1-2v) equation:

6(2-2v)=4(1-2v)

We move all terms to the left:

6(2-2v)-(4(1-2v))=0

We add all the numbers together, and all the variables

6(-2v+2)-(4(-2v+1))=0

We multiply parentheses

-12v-(4(-2v+1))+12=0


We calculate terms in parentheses: -(4(-2v+1)), so:

4(-2v+1)

We multiply parentheses

-8v+4

Back to the equation:

-(-8v+4)


We get rid of parentheses

-12v+8v-4+12=0

We add all the numbers together, and all the variables

-4v+8=0

We move all terms containing v to the left, all other terms to the right

-4v=-8

v=-8/-4

v=+2