6(2-2)=5(2y-2)

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Solution for 6(2-2)=5(2y-2) equation:


Simplifying
6(2 + -2) = 5(2y + -2)

Combine like terms: 2 + -2 = 0
6(0) = 5(2y + -2)

Multiply 6 * 0
0 = 5(2y + -2)

Anything times zero is zero.
0 = 5(2y + -2)

Reorder the terms:
0 = 5(-2 + 2y)
0 = (-2 * 5 + 2y * 5)
0 = (-10 + 10y)

Solving
0 = -10 + 10y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-10y' to each side of the equation.
0 + -10y = -10 + 10y + -10y
Remove the zero:
-10y = -10 + 10y + -10y

Combine like terms: 10y + -10y = 0
-10y = -10 + 0
-10y = -10

Divide each side by '-10'.
y = 1

Simplifying
y = 1

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