6(2-(5+4x))-2x=-20+2(1-13x)

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Solution for 6(2-(5+4x))-2x=-20+2(1-13x) equation: 



6(2-(5+4x))-2x=-20+2(1-13x)

We move all terms to the left:

6(2-(5+4x))-2x-(-20+2(1-13x))=0

We add all the numbers together, and all the variables

6(2-(4x+5))-2x-(-20+2(-13x+1))=0

We add all the numbers together, and all the variables

-2x+6(2-(4x+5))-(-20+2(-13x+1))=0



We calculate terms in parentheses: -(-20+2(-13x+1)), so:

-20+2(-13x+1)

determiningTheFunctionDomain
2(-13x+1)-20

We multiply parentheses

-26x+2-20

We add all the numbers together, and all the variables

-26x-18

Back to the equation:

-(-26x-18)



We get rid of parentheses

-2x+6(2-(4x+5))+26x+18=0

We add all the numbers together, and all the variables

24x+6(2-(4x+5))+18=0

We move all terms containing x to the left, all other terms to the right

24x+6(2-(4x+5))=-18

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