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6(2+y)=3(4-y)
We move all terms to the left:
6(2+y)-(3(4-y))=0
We add all the numbers together, and all the variables
6(y+2)-(3(-1y+4))=0
We multiply parentheses
6y-(3(-1y+4))+12=0
We calculate terms in parentheses: -(3(-1y+4)), so:We get rid of parentheses
3(-1y+4)
We multiply parentheses
-3y+12
Back to the equation:
-(-3y+12)
6y+3y-12+12=0
We add all the numbers together, and all the variables
9y=0
y=0/9
y=0
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