6(2+y)=3(3y-)

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Solution for 6(2+y)=3(3y-) equation: 



6(2+y)=3(3y-)

We move all terms to the left:

6(2+y)-(3(3y-))=0

We add all the numbers together, and all the variables

6(y+2)-(3(+3y))=0

We multiply parentheses

6y-(3(+3y))+12=0



We calculate terms in parentheses: -(3(+3y)), so:

3(+3y)

We multiply parentheses

9y

Back to the equation:

-(9y)



We add all the numbers together, and all the variables

-3y+12=0

We move all terms containing y to the left, all other terms to the right

-3y=-12

y=-12/-3

y=+4

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