6(2+x)=x5+15

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Solution for 6(2+x)=x5+15 equation: 



6(2+x)=x5+15

We move all terms to the left:

6(2+x)-(x5+15)=0

We add all the numbers together, and all the variables

-(+x^5+15)+6(x+2)=0

We multiply parentheses

-(+x^5+15)+6x+12=0

We get rid of parentheses

-x^5+6x-15+12=0

We do not support expression: x^5

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