6(2+x)5x=15

Solution for 6(2+x)5x=15 equation:

6(2+x)5x=15

We move all terms to the left:

6(2+x)5x-(15)=0

We add all the numbers together, and all the variables

6(x+2)5x-15=0

We multiply parentheses

30x^2+60x-15=0

a = 30; b = 60; c = -15;
Δ = b2-4ac
Δ = 602-4·30·(-15)
Δ = 5400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5400}=\sqrt{900*6}=\sqrt{900}*\sqrt{6}=30\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-30\sqrt{6}}{2*30}=\frac{-60-30\sqrt{6}}{60}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+30\sqrt{6}}{2*30}=\frac{-60+30\sqrt{6}}{60}
$