6(2+k)5k=0

Solution for 6(2+k)5k=0 equation:

6(2+k)5k=0

We add all the numbers together, and all the variables

6(k+2)5k=0

We multiply parentheses

30k^2+60k=0

a = 30; b = 60; c = 0;
Δ = b2-4ac
Δ = 602-4·30·0
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3600}=60$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-60}{2*30}=\frac{-120}{60}
=-2
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+60}{2*30}=\frac{0}{60}
=0
$