6(2+4x)+5(4-3x)=7x-19

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Solution for 6(2+4x)+5(4-3x)=7x-19 equation: 



6(2+4x)+5(4-3x)=7x-19

We move all terms to the left:

6(2+4x)+5(4-3x)-(7x-19)=0

We add all the numbers together, and all the variables

6(4x+2)+5(-3x+4)-(7x-19)=0

We multiply parentheses

24x-15x-(7x-19)+12+20=0

We get rid of parentheses

24x-15x-7x+19+12+20=0

We add all the numbers together, and all the variables

2x+51=0

We move all terms containing x to the left, all other terms to the right

2x=-51

x=-51/2

x=-25+1/2

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