6(2+2r)=3(1+7r)

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Solution for 6(2+2r)=3(1+7r) equation: 



6(2+2r)=3(1+7r)

We move all terms to the left:

6(2+2r)-(3(1+7r))=0

We add all the numbers together, and all the variables

6(2r+2)-(3(7r+1))=0

We multiply parentheses

12r-(3(7r+1))+12=0



We calculate terms in parentheses: -(3(7r+1)), so:

3(7r+1)

We multiply parentheses

21r+3

Back to the equation:

-(21r+3)



We get rid of parentheses

12r-21r-3+12=0

We add all the numbers together, and all the variables

-9r+9=0

We move all terms containing r to the left, all other terms to the right

-9r=-9

r=-9/-9

r=1

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