6(1z-4)=4(z+3)

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Solution for 6(1z-4)=4(z+3) equation:


Simplifying
6(1z + -4) = 4(z + 3)

Reorder the terms:
6(-4 + 1z) = 4(z + 3)
(-4 * 6 + 1z * 6) = 4(z + 3)
(-24 + 6z) = 4(z + 3)

Reorder the terms:
-24 + 6z = 4(3 + z)
-24 + 6z = (3 * 4 + z * 4)
-24 + 6z = (12 + 4z)

Solving
-24 + 6z = 12 + 4z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-4z' to each side of the equation.
-24 + 6z + -4z = 12 + 4z + -4z

Combine like terms: 6z + -4z = 2z
-24 + 2z = 12 + 4z + -4z

Combine like terms: 4z + -4z = 0
-24 + 2z = 12 + 0
-24 + 2z = 12

Add '24' to each side of the equation.
-24 + 24 + 2z = 12 + 24

Combine like terms: -24 + 24 = 0
0 + 2z = 12 + 24
2z = 12 + 24

Combine like terms: 12 + 24 = 36
2z = 36

Divide each side by '2'.
z = 18

Simplifying
z = 18

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