6(1x-3)=-48

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Solution for 6(1x-3)=-48 equation: 



6(1x-3)=-48

We move all terms to the left:

6(1x-3)-(-48)=0

We add all the numbers together, and all the variables

6(x-3)-(-48)=0

We add all the numbers together, and all the variables

6(x-3)+48=0

We multiply parentheses

6x-18+48=0

We add all the numbers together, and all the variables

6x+30=0

We move all terms containing x to the left, all other terms to the right

6x=-30

x=-30/6

x=-5

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