6(1x+3)=3(1x-4)

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Solution for 6(1x+3)=3(1x-4) equation: 



6(1x+3)=3(1x-4)

We move all terms to the left:

6(1x+3)-(3(1x-4))=0

We add all the numbers together, and all the variables

6(x+3)-(3(x-4))=0

We multiply parentheses

6x-(3(x-4))+18=0



We calculate terms in parentheses: -(3(x-4)), so:

3(x-4)

We multiply parentheses

3x-12

Back to the equation:

-(3x-12)



We get rid of parentheses

6x-3x+12+18=0

We add all the numbers together, and all the variables

3x+30=0

We move all terms containing x to the left, all other terms to the right

3x=-30

x=-30/3

x=-10

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