6(13c+2)=3c+12

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Solution for 6(13c+2)=3c+12 equation: 



6(13c+2)=3c+12

We move all terms to the left:

6(13c+2)-(3c+12)=0

We multiply parentheses

78c-(3c+12)+12=0

We get rid of parentheses

78c-3c-12+12=0

We add all the numbers together, and all the variables

75c=0

c=0/75

c=0

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