6(1/3d+4)=2(d+12)

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Solution for 6(1/3d+4)=2(d+12) equation: 



6(1/3d+4)=2(d+12)

We move all terms to the left:

6(1/3d+4)-(2(d+12))=0



Domain of the equation: 3d+4)!=0

d∈R



We multiply parentheses

6d-(2(d+12))+24=0



We calculate terms in parentheses: -(2(d+12)), so:

2(d+12)

We multiply parentheses

2d+24

Back to the equation:

-(2d+24)



We get rid of parentheses

6d-2d-24+24=0

We add all the numbers together, and all the variables

4d=0

d=0/4

d=0

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