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6(1/2x+2)-x=(6x+2)+x+1
We move all terms to the left:
6(1/2x+2)-x-((6x+2)+x+1)=0
Domain of the equation: 2x+2)!=0We add all the numbers together, and all the variables
x∈R
-1x+6(1/2x+2)-((6x+2)+x+1)=0
We multiply parentheses
-1x+6x-((6x+2)+x+1)+12=0
We calculate terms in parentheses: -((6x+2)+x+1), so:We add all the numbers together, and all the variables
(6x+2)+x+1
We add all the numbers together, and all the variables
x+(6x+2)+1
We get rid of parentheses
x+6x+2+1
We add all the numbers together, and all the variables
7x+3
Back to the equation:
-(7x+3)
5x-(7x+3)+12=0
We get rid of parentheses
5x-7x-3+12=0
We add all the numbers together, and all the variables
-2x+9=0
We move all terms containing x to the left, all other terms to the right
-2x=-9
x=-9/-2
x=4+1/2
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