6(1-x)-(2x+2)=8+6(x-3)

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Solution for 6(1-x)-(2x+2)=8+6(x-3) equation: 



6(1-x)-(2x+2)=8+6(x-3)

We move all terms to the left:

6(1-x)-(2x+2)-(8+6(x-3))=0

We add all the numbers together, and all the variables

6(-1x+1)-(2x+2)-(8+6(x-3))=0

We multiply parentheses

-6x-(2x+2)-(8+6(x-3))+6=0

We get rid of parentheses

-6x-2x-(8+6(x-3))-2+6=0



We calculate terms in parentheses: -(8+6(x-3)), so:

8+6(x-3)

determiningTheFunctionDomain
6(x-3)+8

We multiply parentheses

6x-18+8

We add all the numbers together, and all the variables

6x-10

Back to the equation:

-(6x-10)



We add all the numbers together, and all the variables

-8x-(6x-10)+4=0

We get rid of parentheses

-8x-6x+10+4=0

We add all the numbers together, and all the variables

-14x+14=0

We move all terms containing x to the left, all other terms to the right

-14x=-14

x=-14/-14

x=1

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