6(1-4x)=-10(x-4)+3x

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Solution for 6(1-4x)=-10(x-4)+3x equation: 



6(1-4x)=-10(x-4)+3x

We move all terms to the left:

6(1-4x)-(-10(x-4)+3x)=0

We add all the numbers together, and all the variables

6(-4x+1)-(-10(x-4)+3x)=0

We multiply parentheses

-24x-(-10(x-4)+3x)+6=0



We calculate terms in parentheses: -(-10(x-4)+3x), so:

-10(x-4)+3x

We add all the numbers together, and all the variables

3x-10(x-4)

We multiply parentheses

3x-10x+40

We add all the numbers together, and all the variables

-7x+40

Back to the equation:

-(-7x+40)



We get rid of parentheses

-24x+7x-40+6=0

We add all the numbers together, and all the variables

-17x-34=0

We move all terms containing x to the left, all other terms to the right

-17x=34

x=34/-17

x=-2

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