6(1+x)=4(x-3)

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Solution for 6(1+x)=4(x-3) equation:



6(1+x)=4(x-3)
We move all terms to the left:
6(1+x)-(4(x-3))=0
We add all the numbers together, and all the variables
6(x+1)-(4(x-3))=0
We multiply parentheses
6x-(4(x-3))+6=0
We calculate terms in parentheses: -(4(x-3)), so:
4(x-3)
We multiply parentheses
4x-12
Back to the equation:
-(4x-12)
We get rid of parentheses
6x-4x+12+6=0
We add all the numbers together, and all the variables
2x+18=0
We move all terms containing x to the left, all other terms to the right
2x=-18
x=-18/2
x=-9

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