6(1+x)=4(1+1/4x)+6+3

Solution for 6(1+x)=4(1+1/4x)+6+3 equation:

6(1+x)=4(1+1/4x)+6+3

We move all terms to the left:

6(1+x)-(4(1+1/4x)+6+3)=0


Domain of the equation: 4x)+6+3)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

6(x+1)-(4(1/4x+1)+6+3)=0

We multiply parentheses

6x-(4(1/4x+1)+6+3)+6=0

We multiply all the terms by the denominator


6x*4x+6*4x+1)+6+3)-(4(1+1)+6+3)=0

We add all the numbers together, and all the variables

6x*4x+6*4x+1)+6+3)-(42+6+3)=0

We add all the numbers together, and all the variables

6x*4x+6*4x=0

Wy multiply elements

24x^2+24x=0

a = 24; b = 24; c = 0;
Δ = b2-4ac
Δ = 242-4·24·0
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-24}{2*24}=\frac{-48}{48}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+24}{2*24}=\frac{0}{48}
=0
$