6(1+x)=2(x+3)

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Solution for 6(1+x)=2(x+3) equation: 



6(1+x)=2(x+3)

We move all terms to the left:

6(1+x)-(2(x+3))=0

We add all the numbers together, and all the variables

6(x+1)-(2(x+3))=0

We multiply parentheses

6x-(2(x+3))+6=0



We calculate terms in parentheses: -(2(x+3)), so:

2(x+3)

We multiply parentheses

2x+6

Back to the equation:

-(2x+6)



We get rid of parentheses

6x-2x-6+6=0

We add all the numbers together, and all the variables

4x=0

x=0/4

x=0

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