6(1+r)-8=-(r+2)

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Solution for 6(1+r)-8=-(r+2) equation: 



6(1+r)-8=-(r+2)

We move all terms to the left:

6(1+r)-8-(-(r+2))=0

We add all the numbers together, and all the variables

6(r+1)-(-(r+2))-8=0

We multiply parentheses

6r-(-(r+2))+6-8=0



We calculate terms in parentheses: -(-(r+2)), so:

-(r+2)

We get rid of parentheses

-r-2

We add all the numbers together, and all the variables

-1r-2

Back to the equation:

-(-1r-2)



We add all the numbers together, and all the variables

6r-(-1r-2)-2=0

We get rid of parentheses

6r+1r+2-2=0

We add all the numbers together, and all the variables

7r=0

r=0/7

r=0

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