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6(1+5v)=5(1+6v)
We move all terms to the left:
6(1+5v)-(5(1+6v))=0
We add all the numbers together, and all the variables
6(5v+1)-(5(6v+1))=0
We multiply parentheses
30v-(5(6v+1))+6=0
We calculate terms in parentheses: -(5(6v+1)), so:We get rid of parentheses
5(6v+1)
We multiply parentheses
30v+5
Back to the equation:
-(30v+5)
30v-30v-5+6=0
We add all the numbers together, and all the variables
1!=0
There is no solution for this equation
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