6(1+3r)=(10r-9)-4r

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Solution for 6(1+3r)=(10r-9)-4r equation: 



6(1+3r)=(10r-9)-4r

We move all terms to the left:

6(1+3r)-((10r-9)-4r)=0

We add all the numbers together, and all the variables

6(3r+1)-((10r-9)-4r)=0

We multiply parentheses

18r-((10r-9)-4r)+6=0



We calculate terms in parentheses: -((10r-9)-4r), so:

(10r-9)-4r

We add all the numbers together, and all the variables

-4r+(10r-9)

We get rid of parentheses

-4r+10r-9

We add all the numbers together, and all the variables

6r-9

Back to the equation:

-(6r-9)



We get rid of parentheses

18r-6r+9+6=0

We add all the numbers together, and all the variables

12r+15=0

We move all terms containing r to the left, all other terms to the right

12r=-15

r=-15/12

r=-1+1/4

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