6(1+3m)=-8(2m+5)+-4

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Solution for 6(1+3m)=-8(2m+5)+-4 equation: 



6(1+3m)=-8(2m+5)+-4

We move all terms to the left:

6(1+3m)-(-8(2m+5)+-4)=0

We add all the numbers together, and all the variables

6(3m+1)-(-8(2m+5)+-4)=0

We use the square of the difference formula

6(3m+1)-(-8(2m+5)-4)=0

We multiply parentheses

18m-(-8(2m+5)-4)+6=0



We calculate terms in parentheses: -(-8(2m+5)-4), so:

-8(2m+5)-4

We multiply parentheses

-16m-40-4

We add all the numbers together, and all the variables

-16m-44

Back to the equation:

-(-16m-44)



We get rid of parentheses

18m+16m+44+6=0

We add all the numbers together, and all the variables

34m+50=0

We move all terms containing m to the left, all other terms to the right

34m=-50

m=-50/34

m=-1+8/17

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