6(1+3)=-8(2m+5)-4

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Solution for 6(1+3)=-8(2m+5)-4 equation: 



6(1+3)=-8(2m+5)-4

We move all terms to the left:

6(1+3)-(-8(2m+5)-4)=0

We add all the numbers together, and all the variables

-(-8(2m+5)-4)+64=0



We calculate terms in parentheses: -(-8(2m+5)-4), so:

-8(2m+5)-4

We multiply parentheses

-16m-40-4

We add all the numbers together, and all the variables

-16m-44

Back to the equation:

-(-16m-44)



We get rid of parentheses

16m+44+64=0

We add all the numbers together, and all the variables

16m+108=0

We move all terms containing m to the left, all other terms to the right

16m=-108

m=-108/16

m=-6+3/4

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