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6(1+1/2x)=2(x=1)
We move all terms to the left:
6(1+1/2x)-(2(x)=0
Domain of the equation: 2x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
6(1/2x+1)-(2x=0
We multiply parentheses
6x-(2x+6=0
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