6(-x-4)+5x=3(10x-8)+10x

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Solution for 6(-x-4)+5x=3(10x-8)+10x equation: 



6(-x-4)+5x=3(10x-8)+10x

We move all terms to the left:

6(-x-4)+5x-(3(10x-8)+10x)=0

We add all the numbers together, and all the variables

6(-1x-4)+5x-(3(10x-8)+10x)=0

We add all the numbers together, and all the variables

5x+6(-1x-4)-(3(10x-8)+10x)=0

We multiply parentheses

5x-6x-(3(10x-8)+10x)-24=0



We calculate terms in parentheses: -(3(10x-8)+10x), so:

3(10x-8)+10x

We add all the numbers together, and all the variables

10x+3(10x-8)

We multiply parentheses

10x+30x-24

We add all the numbers together, and all the variables

40x-24

Back to the equation:

-(40x-24)



We add all the numbers together, and all the variables

-1x-(40x-24)-24=0

We get rid of parentheses

-1x-40x+24-24=0

We add all the numbers together, and all the variables

-41x=0

x=0/-41

x=0

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