6(-8-6x)+8x=-3(7x-5)

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Solution for 6(-8-6x)+8x=-3(7x-5) equation: 



6(-8-6x)+8x=-3(7x-5)

We move all terms to the left:

6(-8-6x)+8x-(-3(7x-5))=0

We add all the numbers together, and all the variables

6(-6x-8)+8x-(-3(7x-5))=0

We add all the numbers together, and all the variables

8x+6(-6x-8)-(-3(7x-5))=0

We multiply parentheses

8x-36x-(-3(7x-5))-48=0



We calculate terms in parentheses: -(-3(7x-5)), so:

-3(7x-5)

We multiply parentheses

-21x+15

Back to the equation:

-(-21x+15)



We add all the numbers together, and all the variables

-28x-(-21x+15)-48=0

We get rid of parentheses

-28x+21x-15-48=0

We add all the numbers together, and all the variables

-7x-63=0

We move all terms containing x to the left, all other terms to the right

-7x=63

x=63/-7

x=-9

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